Saturday, April 20, 2013

Getting Garbled Char When Doing ASCII Math - C And C++ | Dream ...


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    2 Replies - 59 Views - Last Post: Yesterday, 09:17 PM Rate Topic: -----

    #1 gordlonious ?Icon User is offline

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    Posted Yesterday, 05:22 PM

    Here's the code:
    
  #include <stdio.h> #include <stdlib.h> #include <string.h> #include <ctype.h>   int main(int argc, char **argv)  {     char key[10];     char text[10];      key[0] = 'b';     key[1] = 'a';     key[2] = 'c';     key[3] = 'o';     key[4] = 'n';      text[0] = 'h';     text[1] = 'a';     text[2] = 'm';     text[3] = 'a';     text[4] = 'n';      //Declare variables necessary for encryption     int placeofkey = 0;     int placeoftext = 0;     int cypher;      cypher = key[placeofkey] + text[placeoftext];      printf("%c", cypher);      return 0;  }  

    is the cypher = key[placeofkey] + text[placeoftext]; not accessing the ASC11 value? If so, why not? Any help/hint is much appreciated.


    Is This A Good Question/Topic? 0

    Replies To: Getting garbled char when doing ASCII math

    #2 jimblumberg ?Icon User is online

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    Re: Getting garbled char when doing ASCII math

    Posted Yesterday, 08:51 PM

    Quote

    is the cypher = key[placeofkey] + text[placeoftext]; not accessing the ASC11 value?


    This is adding the two characters 'b' + 'h' which is actually 98 + 104 or 202.

    However your printf() function is using an incorrect format specifier. The "%c" specifier is only used for a char, not an int. The correct specifier would be "%d" to print the int cypher.

    Jim


    #3 Skydiver ?Icon User is online

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    Re: Getting garbled char when doing ASCII math

    Posted Yesterday, 09:17 PM

    As an aside: it is ASCII with two i's. Not with two 1's.


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    Source: http://www.dreamincode.net/forums/topic/318931-getting-garbled-char-when-doing-ascii-math/

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